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8-8v^2=-784
We move all terms to the left:
8-8v^2-(-784)=0
We add all the numbers together, and all the variables
-8v^2+792=0
a = -8; b = 0; c = +792;
Δ = b2-4ac
Δ = 02-4·(-8)·792
Δ = 25344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25344}=\sqrt{2304*11}=\sqrt{2304}*\sqrt{11}=48\sqrt{11}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{11}}{2*-8}=\frac{0-48\sqrt{11}}{-16} =-\frac{48\sqrt{11}}{-16} =-\frac{3\sqrt{11}}{-1} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{11}}{2*-8}=\frac{0+48\sqrt{11}}{-16} =\frac{48\sqrt{11}}{-16} =\frac{3\sqrt{11}}{-1} $
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